# Thread: single replacement reaction (chem)

1. ## single replacement reaction (chem)

aluminum + water

what is the molecular equation (balance it)
this is what iget.. its a single replacemnt
Al + h20 -> Al(OH)3 + H2
now i cant figure out how to balance that, if that is even right in the first place..
any help??

2. 2Al + 6H2O ---> 2AL(OH)3 + 3H2

3. Originally Posted by gidget
2Al + 6H2O ---> 2AL(OH)3 + 3H2

ok but here is a question on top of that answer

so we have:
2Al + 6H2O ---> 2AL(OH)3 + 3H2

so to complete this for the net ionic the nex step would be

2Al(s) + 6H2O(l) --> 2AL(OH)3 () + 3H2 (g)

you see the empty parantese.. thats where my problem begins. Using a solubility table, al and oh are a solid. so do i put it as a solid or does the solubility table not apply. if i dot put it as a solid is this correct for the net ionic equation??

2Al(s) + 6H2O(l) --> 2AL(OH)3 (s) + 3H2 (g)

but if i dont put it as a solid and leave it as a (aq) i can get this:

2Al(s) + 6H2O(l) --> 2AL(OH)3 (aq) + 3H2 (g)
2Al(s) + 6H20(l) --> 2Al^+3 (aq) + 3OH-(aq) +3H2(g)

^ is that the correct net ionic or the one where it was a solid thanks hope u can understand my current issue!!