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Math Help - single replacement reaction (chem)

  1. #1
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    single replacement reaction (chem)

    aluminum + water

    what is the molecular equation (balance it)
    this is what iget.. its a single replacemnt
    Al + h20 -> Al(OH)3 + H2
    now i cant figure out how to balance that, if that is even right in the first place..
    any help??
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  2. #2
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    2Al + 6H2O ---> 2AL(OH)3 + 3H2
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  3. #3
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    Quote Originally Posted by gidget View Post
    2Al + 6H2O ---> 2AL(OH)3 + 3H2

    ok but here is a question on top of that answer

    so we have:
    2Al + 6H2O ---> 2AL(OH)3 + 3H2

    so to complete this for the net ionic the nex step would be

    2Al(s) + 6H2O(l) --> 2AL(OH)3 () + 3H2 (g)

    you see the empty parantese.. thats where my problem begins. Using a solubility table, al and oh are a solid. so do i put it as a solid or does the solubility table not apply. if i dot put it as a solid is this correct for the net ionic equation??

    2Al(s) + 6H2O(l) --> 2AL(OH)3 (s) + 3H2 (g)


    but if i dont put it as a solid and leave it as a (aq) i can get this:

    2Al(s) + 6H2O(l) --> 2AL(OH)3 (aq) + 3H2 (g)
    2Al(s) + 6H20(l) --> 2Al^+3 (aq) + 3OH-(aq) +3H2(g)

    ^ is that the correct net ionic or the one where it was a solid thanks hope u can understand my current issue!!
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