Results 1 to 2 of 2

Math Help - Pretty difficult function

  1. #1
    Newbie
    Joined
    Nov 2008
    Posts
    1

    Pretty difficult function

    Here is the function:

    Code:
    x(n) = 61x(n-1) + i + 32
    Basically, it starts at x=0, it multiplies x by 61 and adds 32 and i.

    Assume i is 12,

    1st time: x=44
    2nd time: x=2728


    I need to get x(n-1) starting from the last number

    So for example if I supply x=2728, the answer will give me a reduced value of (44).
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Nov 2008
    Posts
    461
    Hi

    Quote Originally Posted by ken.stend View Post
    Here is the function:

    Code:
    x(n) = 61x(n-1) + i + 32
    Basically, it starts at x=0, it multiplies x by 61 and adds 32 and i.

    Assume i is 12,

    1st time: x=44
    2nd time: x=2728


    I need to get x(n-1) starting from the last number

    So for example if I supply x=2728, the answer will give me a reduced value of (44).

    What exactly is your question, because
    x(n) = 61x(n-1) + i + 32

     x_{n-1} = \frac{x_n - i - 32}{61}

    i.e. x_n = 2728, i=12

    => x_{n-1} = \frac{2728 - 12 - 32}{61} = 44
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Pretty Basic Function Word Problems..
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: February 21st 2010, 08:52 PM
  2. Help Summing Difficult Function
    Posted in the Calculus Forum
    Replies: 4
    Last Post: September 12th 2009, 02:22 PM
  3. difficult sin x function
    Posted in the Trigonometry Forum
    Replies: 8
    Last Post: August 11th 2009, 08:12 AM
  4. Calculation on a distribution function (maybe difficult)
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: April 23rd 2009, 07:56 AM
  5. Pretty difficult
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: May 26th 2008, 12:47 PM

Search Tags


/mathhelpforum @mathhelpforum