Hello,
Have a look here for a similar starting : http://www.mathhelpforum.com/math-he...entiation.html, which should give you ideas as to how you can express this in terms of x.
A piece of wire x m long is cut into two pieces, the length of the first piece being 14 m. The first piece is bent into a circle, and the other is bent into a rectangle with length twice the width. Give an expression for the total area A enclosed in the two shapes in terms of x.
Thank you!
Hello,
Have a look here for a similar starting : http://www.mathhelpforum.com/math-he...entiation.html, which should give you ideas as to how you can express this in terms of x.
Hello, gearshifter!
A tricky one . . . it requires baby-talking our way through it.
A piece of wire m long is cut into two pieces.
The length of the first piece is 14 m and is bent into a circle.
The other is bent into a rectangle with length twice the width.
Give an expression for the total area enclosed in the two shapes in terms of .The wire is: .Code:: 14 P x-14 : * - - - - - * - - - - - * A x B
It is cut at point
Length is bent into a circle.
The circumference of a circle is: .
Since the circumference is 14, we have: .
The area of a circle is: .
. . So we have: .
The other piece, , is bent into a rectangle.
. . Its length is twice its width.Its perimeter isCode:2W * - - - - - - * | | W | | W | | * - - - - - - * 2W
We have: .
And the length is: .
The area of the rectangle is: .
Therefore, the total area is: . square meters.