A machine moves a 600-kg object 6 meters. If the amount of work put into the machine is 4500 joules, what is the efficiency of the machine?

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- November 12th 2008, 06:30 PMPhreshamount of work
A machine moves a 600-kg object 6 meters. If the amount of work put into the machine is 4500 joules, what is the efficiency of the machine?

- November 13th 2008, 12:59 AMKiwi_Dave

You need to calculate the work output of the machine. The efficiency is simply the ratio of work output over work input.

Work = Force x distance.

However, there is not enough information provided to calculate the force. If the object is being lifted then the force is 9.81 x 600. If the object is being dragged across a horizontal surface then the force is dependent on a coefficient of friction. There are many other possibilities, the object could be dragged up a hill or through a viscous fluid.