I do the following:
so, (6x^2-8x+3)/2x is the f'(x) according to what I just did
but the book says the answer is (2x^3-6)/(x^3)
I'll post more of this nature that I screwed up if however you help me solve this won't suffice for the other, similar problems
Let g(x) = 9f(x) and let f'(-6) = -6. Find g'(-6).
I don't even know where to begin here.