Hi mate

Thats wrong.

(+3)' = 0

This term has no x in it!

Thats Ok.

You must use the Quotient rule

I guess there are many solutions for this problem.

One of them is very simple:

f'(-6) = -6

I guess f(x) = mx+b, you know f'(-6) = -6 = m

=> f(x) = -6x + b

g(x) = 9f(x) = 9*(-6x+b) = -54x + 9b

g'(x) = -54

You just have to find a function with f'(-6) = -6, it isnt that hard, (then to findd the antiderivative) and multiply it with 9.