Would anybody happen to know how to express this in terms of X?

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- Nov 8th 2008, 09:22 PMgearshifterExpressing in terms of X
Would anybody happen to know how to express this in terms of X?

- Nov 8th 2008, 09:32 PMmr fantastic
Read this thread for a way of doing questions like this: http://www.mathhelpforum.com/math-he...xpression.html

- Nov 9th 2008, 02:08 PMHallsofIvy
Saying is the same as saying . Since tangent is "opposite side over near side", if we imagine a right triangle with legs of length 7 and x, is the angle opposite the leg of length 7. Now we can use the Pythagorean theorem to find the length, c, of the hypotenuse: so .

Now secant is 1/sine or "hypotenuse divided by opposite side" which, here, is . Finally, .