I have no idea how to do this question..
Please Simplify:
cos^2(cos^(-1)(6/x))
Please see the attached for info
Thanks!
That is the same as $\displaystyle \left(cos(cos^{-1}(6/x))\right)^2$. IMPORTANT: the "-1" on the cos mean "inverse function" not reciprocal! You should know that $\displaystyle f(f^{-1})(x)= x$.