Hello,
How do I find the turning point of a parabola?
Thanks in advance
The turning point of a parabola is the vertex of the parabola.
For the given equation of parabola, you can find the vertex by completing the square in the form
$\displaystyle y = a(x-h)^2+k$
where (h, k) is vertex.
If, suppose equation of a parabola is
$\displaystyle y = 3x^2-6x+5$
Then, complete the square, so, eqn becomes,
$\displaystyle y = 3(x-1)^2+2$
so, vertex = (1, 2)
so, turning point = (1, 2)
Did you get it now???
Shyam - no, I'm afraid that just confuses me even more.
I think my lecturer gave the formula: -b/2a to find the x-component of the vertex, then may have said to substitute that value into another equation to find the y-component.
Does this sound right or am I way off?
that formula is correct, for example, take this function;
y=x^2+6x+8
b=6, a=1
-b/2a=-6/2(1)=-3
sub -3 into the function to get the value of y
y=(-3)^2+6(-3)+8=-1
therefore, the vertex for this example is (-3,-1)
Shyam is simply using another method then the one you are instructed to use