http://i255.photobucket.com/albums/h...hdude/math.jpg
How would I go about solving this?
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http://i255.photobucket.com/albums/h...hdude/math.jpg
How would I go about solving this?
First make it a "Y=" equation.
Y = x2-5x+6
Switch the Y with the x's
X = Y2-5Y+6
Solve for X
X-6 = Y2-5Y
X-6/5 = Y2
Square root of ((x-6)/5)) = Y
Kind of confusing, but I hope this helps!
The easiest way to go abouts doing this is making a table of values for the function and switching the values of the y and x. what i mean is make the x values the y values and the y values the x values. This will give you the inverse, f-1(x)Quote:
Originally Posted by Aske
You don't. That is not a "one to one" function and so does not have an inverse. IfQuote:
Originally Posted by Aske
is the inverse of f(x), then we must have
, that is,
must 'undo' whatever f does. But f(6)= 0 and f(-1)= 0.
can't be both 6 and -1!
Luke774, for some reason, chose to take only the "+" sign on the square root. That's valid but gives the inverse of a slightly different function:with
and undefined for x< 5/2. Same formula but different domain so different function.