Originally Posted by

**bobbymellor** The example starts as so,

a crate has a square base of width (and length) x metres and is of height h metres. The haulage company will only transport crates provided that the sum of the length, width and height of a crate is not more than 5 metres. The firm wishes to maximise the volume V of the crate.

I want to explain why h = 5 - 2X if we want to maximise V,

and also to show that the quantity to be maximised is V = 5X^2 - 2X^3

not really sure ive got a grip on this one any help appreciated

- bobby