$\displaystyle 3y/(y-1) = x$ I can't seem to make y the subject of the above formula....I must be having some kind of mental lapse here!
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Originally Posted by Ant $\displaystyle 3y/(y-1) = x$ I can't seem to make y the subject of the above formula....I must be having some kind of mental lapse here! $\displaystyle \frac{3y}{y - 1} = x$ $\displaystyle \Rightarrow 3y = x(y - 1) = xy - x $ $\displaystyle \Rightarrow 3y - xy = -x$ $\displaystyle \Rightarrow y (3 - x) = -x$ $\displaystyle \Rightarrow y = \frac{-x}{3 - x} = \frac{x}{x - 3}$.
thankyou!
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