e^ln2 = 2 Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)? Thanks.
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Hello, Originally Posted by Ant e^ln2 = 2 Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)? Thanks. Yes it's because they're inverses. $\displaystyle \forall x \in \mathbb{R}, ~ \ln(e^x)=x$ $\displaystyle \forall x \in (0,+\infty),~ e^{\ln(x)}=x$
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