# Help with Logs

• November 1st 2008, 10:06 AM
Ant
Help with Logs
e^ln2 = 2

Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)?

Thanks.
• November 1st 2008, 10:19 AM
Moo
Hello,
Quote:

Originally Posted by Ant
e^ln2 = 2

Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)?

Thanks.

Yes it's because they're inverses.

$\forall x \in \mathbb{R}, ~ \ln(e^x)=x$

$\forall x \in (0,+\infty),~ e^{\ln(x)}=x$