e^ln2 = 2

Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)?

Thanks.

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- Nov 1st 2008, 10:06 AMAntHelp with Logs
e^ln2 = 2

Is this correct? if so, can anoyone explain it to me please, I can see how perhaps the e and ln cancel each other out (being inverses)?

Thanks. - Nov 1st 2008, 10:19 AMMoo