Wavelength Help Needed

**drew1000** · October 31st 2008, 08:50 AM

How do I calculate the wavelength of an 1800 MHz signal

**Rafael Almeida** · October 31st 2008, 08:57 AM

Velocity, wavelength, and frequency of a wave relate by the following rule:

$v = \lambda f$ , where $\lambda$ is the wavelength.

If the wave is a signal, as in radio or television or whatever signal, it is a eletromagnetic wave. Does this ring a bell for you as to the velocity of the wave?

**masters** · October 31st 2008, 09:12 AM

Originally Posted by drew1000

How do I calculate the wavelength of an 1800 MHz signal

$\lambda=\frac{c}{v}$ where c=speed of light in a vacuum ( $3 \times 10^8 \ \ m/s \ \ or \ \ 3 \times 10^{10} \ \ cm/s)$ and v = frequency in hertz (hz).

$1800 \ \ Mhz \ \ =1.8 \times 10^9 \ \ hz$

**drew1000** · October 31st 2008, 09:16 AM

What is the answer if it is a mobile phone signal

**Rafael Almeida** · October 31st 2008, 09:30 AM

Originally Posted by drew1000

What is the answer if it is a mobile phone signal

A mobile phone signal is a eletromagnetic wave, and as 'masters' correctly pointed out, and all eletromagnetic waves have the speed of light, $c$ , in the vacuum. This speed is very similar to that in the air, so you just ignore the difference.

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