Results 1 to 2 of 2

Math Help - Algebra....

  1. #1
    Ant
    Ant is offline
    Member
    Joined
    Apr 2008
    Posts
    137
    Thanks
    4

    Algebra....

    I Really have no idea about how to approach this one...

    2/[y(y+1)] can be expressed in form 2/y - 2/y+1

    thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,393
    Thanks
    1327
    Quote Originally Posted by Ant View Post
    I Really have no idea about how to approach this one...

    2/[y(y+1)] can be expressed in form 2/y - 2/y+1

    thanks
    That's called "partial fractions". Suppose \frac{2}{y(y+1)}= \frac{A}{y}+ \frac{B}{y+1}. Multiply on both sides by y(y+1) to get rid of the fractions: 2= A(y+1)+ By. That must be true for all y so you can take any value for y you want. In particular, taking y= 0 give 2= A and taking y= -1 gives 2= -B.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: February 4th 2011, 08:39 AM
  2. Replies: 2
    Last Post: December 6th 2010, 03:03 PM
  3. Algebra or Algebra 2 Equation Help Please?
    Posted in the Algebra Forum
    Replies: 4
    Last Post: May 12th 2010, 11:22 AM
  4. Replies: 0
    Last Post: April 23rd 2010, 11:37 PM
  5. algebra 2 help
    Posted in the Algebra Forum
    Replies: 3
    Last Post: January 4th 2009, 06:24 PM

Search Tags


/mathhelpforum @mathhelpforum