Factor a "minus" out of the middle denominator . . .2. Add/subtract: .
We have: .
1. Simplify the expression
I know it goes to this
I eventually get it down to b-a/2ab
But I guess that's incorrect? I think it has to do with how I'm making the denominators equal.
don't know how to find the lcd?
is the lcd (1+x)(1-x)(x-1)?
thanks for help in advance.
Thanks for the help both of you.
2. The summands contains powers therefore you have to use the rules of calculating powers.
3. At this point I used the rules of adding fractions. I didn't write the fractions because I was pretty sure that you see that
4. The followings steps are nothing but factor out common factors from partial sums.