I need to know what formula is required to solve this problem

A pail of water is swung by a cord tied to its handle in a vertical circle

of radius 9.76 E-01m.

What must be its minimum speed at the top of the circle if no water is

to spill out?

Printable View

- Oct 27th 2008, 05:43 AMjohn haascentripetal force.
I need to know what formula is required to solve this problem

A pail of water is swung by a cord tied to its handle in a vertical circle

of radius 9.76 E-01m.

What must be its minimum speed at the top of the circle if no water is

to spill out? - Oct 27th 2008, 07:35 AMRafael Almeida
john,

The formula for centripetal force is , where m is the mass, v the the velocity and R is the radius of the movement. - Oct 27th 2008, 07:46 AMChop Suey
- Oct 27th 2008, 08:00 AMjohn haasneed mass
Rafael

Thanks for supplying the formula.

What if I am not given mass.

All that is given is the radius and acceleration as gravity(9.81m/s^2).

from the above I was able to solve velocity as 3.09 m/s

I am thinking at the top of the vertical would I use a negative acceleration.

Thanks for your help - Oct 27th 2008, 08:15 AMRafael Almeida
john,

As Chop Suey correctly pointed out, at the top of the circle, the force that mantains the motion is ONLY the gravitational force (weight). This happens because this force will be applied no matter what, and a stronger force would imply a higher velocity by the formula I gave you.

Since you know the force is the weight:

Also notice that, considering the centripetal force to be constant and using Newton's Second Law:

What gives you the modulus of the centripetal acceleration for any point in the circle, which does not depend on mass. So, another argument to solve the question is to see that, since no other force other than weight is applied to the pail, its acceleration must be equal to gravity. Setting in the above formula will lead you to the same result as in (I).

Hope this helps,