hi]

two pipes a and b can seperately fill a tank in 20 mins and 30 mins respectively, which a third pipe C can empty the full tank iin 15 mins

If all pipes are opened together then in what time is the empty tank filled?

bye

gautam93

Results 1 to 4 of 4

- September 16th 2006, 01:01 AM #1

- Joined
- Sep 2006
- From
- mumbai
- Posts
- 8

- September 16th 2006, 01:28 AM #2

- Joined
- Nov 2005
- From
- someplace
- Posts
- 14,972
- Thanks
- 4

The first pipe fills the tank at a rate of 1/20 of a tank/min

The second pipe fills the tank at a rate of 1/30 of a tank/min

The third pipe empties the tank at a rate of 1/15 of a tank/min.

Starting from empty the content of the tank at time t is:

t(1/20+1/30-1/15).

The solution is the time t for which:

t(1/20+1/30-1/15)=1,

which is 60 minutes.

RonL

- September 16th 2006, 05:02 PM #3

- Joined
- Nov 2005
- From
- New York City
- Posts
- 10,616
- Thanks
- 10

- September 17th 2006, 12:51 AM #4

- Joined
- Nov 2005
- From
- someplace
- Posts
- 14,972
- Thanks
- 4

Your rule does not lead to understanding, while the reason for it does.

Though it seems to be the fashion of the day, I would discourage

learning rules at the expense of understanding. I normally work many

things, others seem to use rules for, from more primitive principles.

RonL