# V as a function of H

• Oct 23rd 2008, 07:58 AM
gearshifter
V as a function of H
V = (3-(r^2/3))h and h/(2-r) = 5/2

Write V as a function of H.

Simplify the function so that you can express it as a polynomial in H.
• Oct 23rd 2008, 10:42 AM
Showcase_22
Quote:

Originally Posted by gearshifter
V = (3-(r^2/3))h and h/(2-r) = 5/2

Write V as a function of H.

Simplify the function so that you can express it as a polynomial in H.

$V=(3-r^{\frac{2}{3}})h$

$\frac{h}{2-r}=\frac{5}{2}$

Rearranging gives:

$h=\frac{5(2-r)}{2}$

$2h=10-5r$

$2h-10=-5r$

$r=\frac{10-2h}{5}$

$r=2-\frac{2h}{5}$

Now substitute the second one into the first one and you're home dry!
• Oct 23rd 2008, 06:24 PM
gearshifter
I got:

(-4h^3+125h)/75

as my final answer.

Would anybody know if it is correct?
• Oct 25th 2008, 05:28 AM
Showcase_22
We know that:

$
V=(3-r^{\frac{2}{3}})h
$

and

$
r=2-\frac{2h}{5}
$

Therefore:

$V=(3-(2-\frac{2h}{5})^{\frac{2}{3}})h$

hmm, I can't actually see a way of cancelling it down from here, can you post your working?