Hello,

An object is released from a height of 25M. How far has the object travelled during the 3rd second of fall?

I don't really know how to do this - what formula/'s should I use?

thanks!

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- October 22nd 2008, 05:05 PMjeepwheelerDropping object from height
Hello,

An object is released from a height of 25M. How far has the object travelled during the 3rd second of fall?

I don't really know how to do this - what formula/'s should I use?

thanks! - October 22nd 2008, 05:26 PMvincisonfire
Formula is

You can find that object touches the ground at 2.26 seconds

Find how far it went at 2 seconds and do 25m minus this answer - October 22nd 2008, 05:32 PMShyamReply
The formula is

where h = height

u = initial velocity (which is 0 here)

g = accleration due to gravity

t = time. - October 22nd 2008, 05:35 PMjeepwheeler
Got it - thanks a lot! Oddly worded question, that was the tough part.

- October 22nd 2008, 05:36 PMvincisonfire
Don't you think the object should travel further during the 3rd second.

It starts from heigth 25 m. And goes down 19 m in two seconds as you said.

It is going to make the rest (6m) in the third second. - October 22nd 2008, 06:02 PMShyam
- October 22nd 2008, 06:17 PMskeeter
it only takes a bit over 2.2 seconds to hit the ground from a height of 25 m, so asking how far it travels in the third second is poorly posed.

if it had enough height to fall the "third" second, then from t = 2 to t = 3 seconds ...

if the intent was to determine the distance it fell from t = 2 seconds until it hits the ground, ...

leaving 5.4 m to fall from t = 2 to impact.