Originally Posted by

**EyesForEars** Ok. I understand that a complex number can be written in the form...a+bi.

Which leads me to the idea that

__(5-6i)-4i is equivalent to (5-6i)-(0-4i).__

The above should be written (5-6i)-4i = (5-6i) - (0 + 4i). Remember, when you put grouping symbols around an expression and precede the group with a negative sign, each sign within the group must be changed to its opposite.

-4i = -(+4i)

Which gives me 5-2i as a solution, because 5-0=5 and -6i-(-4i) is -2i. __So.. (5-6i)-4i = 5-2i__

Removing the parentheses on the above we get 5 - 6i - 4i = __5 - 10i__

Is this a true statement?

My text says no, and I can't wrap my head around it.

P.S. (a+bi)-(c+di)= a+bi-c-di = (a-c)+(b-d)i

Using this, we get (5-6i)-(0+4i) = 5-6i-0-4i = (5-0)+(-6-4)i = 5-10i