Ok. I understand that a complex number can be written in the form...a+bi.
Which leads me to the idea that
(5-6i)-4i is equivalent to (5-6i)-(0-4i).
Which gives me 5-2i as a solution, because 5-0=5 and -6i-(-4i) is -2i. So..
(5-6i)-4i = 5-2i
Is this a true statement?
My text says no, and I can't wrap my head around it.
P.S. (a+bi)-(c+di)= a+bi-c-di = (a-c)+(b-d)i