Assistance is needed.

**gedprep** · October 8th 2008, 06:29 AM

n
2=n+1

can you help me solve this?

**masters** · October 8th 2008, 06:45 AM

Originally Posted by gedprep

n
2=n+1

can you help me solve this?

This is an addition equation because a value has been added to the variable n.
To isolate the variable (get the variable by itself on one side of the equation),
you must perform the inverse of addition (subtraction) on the value.

$2=n+1$

Subtract 1 from both sides

$2-1=n+1-1$

$1=n$

$\boxed{n=1}$

**gedprep** · October 8th 2008, 06:51 AM

I am sorry but tis was 2 over n equals n plus 1

**masters** · October 8th 2008, 07:03 AM

Originally Posted by gedprep

I am sorry but tis was 2 over n equals n plus 1

$\frac{2}{n}=n+1$

First, multiply each term by n

$2=n^2+n$

Now, set the equation = 0

$n^2+n-2=0$

Now, factor the trinomial

$(n+2)(n-1)=0$

Using the zero product property that says "If ab=0, then a=0 or b=0",

$n+2=0 \ \ or \ \ n-1=0$

$n=-2 \ \ or \ \ n=1$

**gedprep** · October 8th 2008, 08:36 AM

I am sorry but it is n over 2 equals n plus 1

not 2 over n

**masters** · October 8th 2008, 08:47 AM

Originally Posted by gedprep

I am sorry but it is n over 2 equals n plus 1

not 2 over n

Third time's the charm...

$\frac{n}{2}=n+1$

Multiply all terms by 2 (in order to eliminate the fraction)

$n=2n+2$

Subtract 2n from each side.

$-n=2$

Multiply everything by -1.

$n=-2$

**gedprep** · October 8th 2008, 08:56 AM

why must you multiply the 1 as well as the number n?

**masters** · October 8th 2008, 09:46 AM

Originally Posted by gedprep

why must you multiply the 1 as well as the number n?

One of the 10 commandants of math is:

Thou shalt do unto one side of an equation what thou doest to the other.

If I multiply 2 times one term in an equation, I must multiply 2 times every term in the equation.

Example:

$\frac{x}{2}+3=2x-1$

Multiple all terms by 2.

${\color{red}2}\left(\frac{x}{2}\right)+{\color{red }2}(3)={\color{red}2}(2x)-{\color{red}2}(1)$

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