n
2=n+1
can you help me solve this?
This is an addition equation because a value has been added to the variable n.
To isolate the variable (get the variable by itself on one side of the equation),
you must perform the inverse of addition (subtraction) on the value.
$\displaystyle 2=n+1$
Subtract 1 from both sides
$\displaystyle 2-1=n+1-1$
$\displaystyle 1=n$
$\displaystyle \boxed{n=1}$
$\displaystyle \frac{2}{n}=n+1$
First, multiply each term by n
$\displaystyle 2=n^2+n$
Now, set the equation = 0
$\displaystyle n^2+n-2=0$
Now, factor the trinomial
$\displaystyle (n+2)(n-1)=0$
Using the zero product property that says "If ab=0, then a=0 or b=0",
$\displaystyle n+2=0 \ \ or \ \ n-1=0$
$\displaystyle n=-2 \ \ or \ \ n=1$
One of the 10 commandants of math is:
Thou shalt do unto one side of an equation what thou doest to the other.
If I multiply 2 times one term in an equation, I must multiply 2 times every term in the equation.
Example:
$\displaystyle \frac{x}{2}+3=2x-1$
Multiple all terms by 2.
$\displaystyle {\color{red}2}\left(\frac{x}{2}\right)+{\color{red }2}(3)={\color{red}2}(2x)-{\color{red}2}(1)$