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Math Help - Please Help

  1. #1
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    Please Help

    Sami, Ben, and Louis went to lunch. Ben's meal cost $0.45 less than Sami's. Louis's meal cost twice as much as Ben's. If the bill came to $9.25, how much does each owe? s= Sami's share

    Can anybody put this together and solve it?

    Equation?
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  2. #2
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    Ben's meal cost $0.45 less than Sami's.

    B = S - .45

    Louis's meal cost twice as much as Ben's.

    L = 2B = 2(S - .45)

    the bill came to $9.25

    S + B + L = 9.25

    substitute for B and L, then solve for S ... finding B and L will then be easy.
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  3. #3
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    I'm sorry but I did not understand B and L.
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  4. #4
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    B = price of Ben's meal

    L = price of Louis' meal
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  5. #5
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    Re: Please Help

    The equation says to solve for Sami so we'll use S in the equation S+(S-0.45)+2(S-0.45)=9.25 use distributive property S+S-0.45+2S-0.90=9.25 now collect the variables 4S-1.35=9.25 now isolate the variable by adding 1.35 to both sides now you have 4S=10.60 now to get the variable by itself divide both sides by 4 now you have S=2.65 we know Ben paid 0.45 less then Sam so B= 2.65-0.45=2.20 and louis paid twice as much as Ben so L=2(2.20)=4.40 now add S+B+L 2.65+2.20+4.40=9.25
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  6. #6
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    Re: Please Help

    Quote Originally Posted by MYSTICK121179 View Post
    The equation says to solve for Sami so we'll use S in the equation S+(S-0.45)+2(S-0.45)=9.25 use distributive property S+S-0.45+2S-0.90=9.25 now collect the variables 4S-1.35=9.25 now isolate the variable by adding 1.35 to both sides now you have 4S=10.60 now to get the variable by itself divide both sides by 4 now you have S=2.65 we know Ben paid 0.45 less then Sam so B= 2.65-0.45=2.20 and louis paid twice as much as Ben so L=2(2.20)=4.40 now add S+B+L 2.65+2.20+4.40=9.25
    You do you realize this thread is almost 4 years old?
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