2 over 3 (y-3) = 1 over 3 y

Can anybody solve this for me?

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- Oct 7th 2008, 01:56 PM #1

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- Oct 7th 2008, 02:02 PM #2

- Oct 7th 2008, 02:05 PM #3

- Oct 7th 2008, 02:09 PM #4
The first thing that I would do would be to distribute the $\displaystyle \frac{2}{3}$ throughout the parenthesis.

This will give you $\displaystyle \frac{2}{3}(y)-\frac{2}{3}(3)=\frac{1}{3}y$

Simplifying, you get $\displaystyle \frac{2}{3}y-2=\frac{1}{3}y$

Can you take it from here? All you need to do is get y on one side of the equation, and everything else on the other.

--Chris