• October 7th 2008, 01:56 PM
gedprep
2 over 3 (y-3) = 1 over 3 y

Can anybody solve this for me?
• October 7th 2008, 02:02 PM
Chris L T521
Quote:

Originally Posted by gedprep
2 over 3 (y-3) = 1 over 3 y

Can anybody solve this for me?

Do you mean

$\frac{2}{3(y-3)}=\frac{1}{3y}$

Or

$\frac{2}{3}(y-3)=\frac{1}{3}y$ ???

--Chris
• October 7th 2008, 02:05 PM
gedprep
The 2nd one

(Smirk)
• October 7th 2008, 02:09 PM
Chris L T521
The first thing that I would do would be to distribute the $\frac{2}{3}$ throughout the parenthesis.

This will give you $\frac{2}{3}(y)-\frac{2}{3}(3)=\frac{1}{3}y$

Simplifying, you get $\frac{2}{3}y-2=\frac{1}{3}y$

Can you take it from here? All you need to do is get y on one side of the equation, and everything else on the other.

--Chris