2 over 3 (y-3) = 1 over 3 y
Can anybody solve this for me?
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2 over 3 (y-3) = 1 over 3 y
Can anybody solve this for me?
Do you meanQuote:
Originally Posted by gedprep
$\displaystyle \frac{2}{3(y-3)}=\frac{1}{3y}$
Or
$\displaystyle \frac{2}{3}(y-3)=\frac{1}{3}y$ ???
--Chris
The 2nd one
(Smirk)
The first thing that I would do would be to distribute the $\displaystyle \frac{2}{3}$ throughout the parenthesis.
This will give you $\displaystyle \frac{2}{3}(y)-\frac{2}{3}(3)=\frac{1}{3}y$
Simplifying, you get $\displaystyle \frac{2}{3}y-2=\frac{1}{3}y$
Can you take it from here? All you need to do is get y on one side of the equation, and everything else on the other.
--Chris
