Can anyone help me solve this problem please?
-2(2y+1)=6
$\displaystyle -2(2y+1)=6$
Distribute (multiply) -2 across the sum (2y+1)
$\displaystyle -4y-2=6$
Add 2 to both sides of the equation.
$\displaystyle -4y-2+2=6+2$
$\displaystyle -4y=8$
Finally, divide both sides by -4
$\displaystyle \frac{-4y}{-4}=\frac{8}{-4}$
$\displaystyle \boxed{y=-2}$