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Thread: Solving an equation with parentheses

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    Solving an equation with parentheses

    Can anyone help me solve this problem please?



    -2(2y+1)=6
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  2. #2
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    Quote Originally Posted by gedprep View Post
    Can anyone help me solve this problem please?



    -2(2y+1)=6
    $\displaystyle -2(2y+1)=6$

    Distribute (multiply) -2 across the sum (2y+1)

    $\displaystyle -4y-2=6$

    Add 2 to both sides of the equation.

    $\displaystyle -4y-2+2=6+2$

    $\displaystyle -4y=8$

    Finally, divide both sides by -4

    $\displaystyle \frac{-4y}{-4}=\frac{8}{-4}$

    $\displaystyle \boxed{y=-2}$
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