- points x and y lie on cordinate axises
- the line CD is disected into 3 parts by x and y equally (trisected is the term?)
- we are given the value of C to find the possible cordinates of D
Can someone lead me in the right direction, I'm not exactly looking for answers here.
(this is for saturday school math, no idea how to, ty, im in grade 9 btw)
For example, say C = (1,3) and X = (7, 9).
If Y is the midpoint of CX, then Y = (4, 6). and D = X + <CY> = (7, 9) + <3, 3> = (10, 12).
If X is the midpoint of CY, then Y = (13, 15) and D = Y + <CX> = (13, 15) + <6, 6> = (19, 21).
Ok, I have a better understanding of the question now. You are given C only, and you have to find D, but you know that X and Y lie on the coordinate axes. Assuming that C does not lie on an axis, then you will have two possibilities for the location of D. Let C = (a, b) and define X to be the midpoint of CY. Then, because Y lies on an axis, it is either (0, y) for some y or (x, 0) for some x. If Y is (0, y), then X = , which means Y = (0, -b). If Y is (x, 0), then X = , which means Y = (-a, 0). Can you determine the possible locations of D from this information?
and uh, how did you conclude to Y(0,-b) after finding the x-coordinate midpoint. because when I do it, I have two variables to average out. and i also know that once i have the two coordinates of X and Y, I can find the distance between X and Y using that distance to substitute in a distance formula of Y and D, but for D I have two variables, how would I solve for each.
A vector is a quantity that has length and direction. For example, the vector connecting the two points (1,1) and (4,5) is <3, 4> and it has a length of 5. It represents, in this case, the difference between the coordinates of the two points. If I add <3, 4> to (4, 5) I get (7, 9). Because I added the same vector twice, it turns out that (4, 5) is the midpoint of the line segment connecting (1, 1) and (7, 9).