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Math Help - unitary method

  1. #1
    Newbie joshirabi's Avatar
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    Thumbs up unitary method

    please do this problem using chain rule
    A, B and C can finish a piece of work in 30, 40, and 60 days respectively. 10 days after they started to work together B leaves. 4 days after B left, A leaves and C completes the remaining work. Find how many days C had worked altogether.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by joshirabi
    please do this problem using chain rule
    A, B and C can finish a piece of work in 30, 40, and 60 days respectively. 10 days after they started to work together B leaves. 4 days after B left, A leaves and C completes the remaining work. Find how many days C had worked altogether.
    I don't know what you think the chain rule is but here is a solution.

    A does 1/30 of the work per day, B does 1/40 and C 1/60.

    Total work done by B is 10/40=1/4. Total work done by A is 14/30=7/15.

    So total work done by A and B is 1/4+7/15=43/60, leaving 17/60 of the
    work to be done by C. However C does 1/60 of the work per day, hence
    works for a total of 17 days.

    RonL
    Last edited by CaptainBlack; September 7th 2006 at 02:16 AM.
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  3. #3
    Newbie joshirabi's Avatar
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    thanks

    chain rule is
    making fraction of ratio
    take two product of fractions
    equlize the product
    suppose the value by x
    making two product equlize
    and find the value of x
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by joshirabi
    chain rule is
    making fraction of ratio
    take two product of fractions
    equlize the product
    suppose the value by x
    making two product equlize
    and find the value of x
    And there was I thinking it was something to do with taking derivatives

    RonL
    Thanks from hamidxhiphop
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