[SOLVED] Ratio of the second term to the first term

• September 25th 2008, 10:22 PM
fabxx
[SOLVED] Ratio of the second term to the first term
------615

After the first term, each term in a sequence is 3 greater than $\frac {1}{3}$ of the preceding term. If t is the first term of the sequence and t≠0, what is the ratio of the second term to the first term?

Can you please explain how you got the answer? Thank you so much!!
• September 25th 2008, 10:24 PM
Jhevon
Quote:

Originally Posted by fabxx
------615

After the first term, each term in a sequence is 3 greater than $\frac {1}{3}$ of the preceding term. If t is the first term of the sequence and t≠0, what is the ratio of the second term to the first term?

Can you please explain how you got the answer? Thank you so much!!

um, you just want the $\frac {\text{second term}}{\text{first term}}$

and they told you how to get the second term from the first
• September 25th 2008, 10:28 PM
fabxx
The correct answer is $\frac{t+9}{3t}$ I don't know why this is the correct answer. Please help. Thanks a lot!!
• September 26th 2008, 04:55 AM
mr fantastic
Quote:

Originally Posted by fabxx
------615

After the first term, each term in a sequence is 3 greater than $\frac {1}{3}$ of the preceding term. If t is the first term of the sequence and t≠0, what is the ratio of the second term to the first term?

Can you please explain how you got the answer? Thank you so much!!

Quote:

Originally Posted by Jhevon
um, you just want the $\frac {\text{second term}}{\text{first term}}$

and they told you how to get the second term from the first

$t, \, \frac{1}{3} t + 3, \, ...$

Quote:

Originally Posted by fabxx
The correct answer is $\frac{t+9}{3t}$ I don't know why this is the correct answer. Please help. Thanks a lot!!

Where do you get stuck from here?
• September 26th 2008, 06:13 AM
fabxx
Thanks. I get it now.