In one year, Carol earned the same amount of interest from an

investment at 8% annual interest as an investment at 12% annual

interest. She had invested $1500 more at 8%. How much money did she

have invested 12%?

Unknowns:

x = amount invested at 8%

y = amount invested at 12%

First Eq:

Interest from 8% = Interest from 12%

x * (1 + 0.08) = y * (1 + 0.12)

Second Eq:

amount invested at 8% = amount invested at 12% + $1500

x = y + 1500

The second one is solved, I plug it into the fist one, Do that equation, and that makes the amount invested at 8% = 39k?

SO... After all the yada yada, the amount invested at12% = $37,500?

No? or did I do something wrong?

Thanks