In one year, Carol earned the same amount of interest from an
investment at 8% annual interest as an investment at 12% annual
interest. She had invested $1500 more at 8%. How much money did she
have invested 12%?
x = amount invested at 8%
y = amount invested at 12%
Interest from 8% = Interest from 12%
x * (1 + 0.08) = y * (1 + 0.12)
amount invested at 8% = amount invested at 12% + $1500
x = y + 1500
The second one is solved, I plug it into the fist one, Do that equation, and that makes the amount invested at 8% = 39k?
SO... After all the yada yada, the amount invested at12% = $37,500?
No? or did I do something wrong?