Results 1 to 2 of 2

Thread: Integers (549)

  1. #1
    Member
    Joined
    Sep 2008
    Posts
    222

    Integers (549)

    If a, b, and c are different positive integers and $\displaystyle (2^a )( 2^b) ( 2^c) =64, then 2^a + 2^b +2^c = $

    (2^a)(2^b)(2^c)--> multiply
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member Peritus's Avatar
    Joined
    Nov 2007
    Posts
    397
    if
    $\displaystyle
    (2^a )( 2^b) ( 2^c) =64$

    then:

    $\displaystyle a + b + c = 6$

    we're told that a,b,c are positive different integers so the only possible option is:

    $\displaystyle a = 1, b = 2, c = 3$

    or some other permutation of the above which all give the same answer:

    $\displaystyle
    2^a + 2^b + 2^c = 2 + 4 + 8 = 14$
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: Dec 5th 2011, 11:47 PM
  2. Replies: 7
    Last Post: Aug 3rd 2010, 01:31 PM
  3. Matrix of integers whose inverse is full of integers
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: Mar 19th 2010, 02:02 PM
  4. Replies: 4
    Last Post: Feb 24th 2008, 03:08 PM
  5. Replies: 2
    Last Post: Oct 14th 2007, 03:18 PM

Search Tags


/mathhelpforum @mathhelpforum