1. ## Integers (549)

If a, b, and c are different positive integers and $(2^a )( 2^b) ( 2^c) =64, then 2^a + 2^b +2^c =$

(2^a)(2^b)(2^c)--> multiply

2. if
$
(2^a )( 2^b) ( 2^c) =64$

then:

$a + b + c = 6$

we're told that a,b,c are positive different integers so the only possible option is:

$a = 1, b = 2, c = 3$

or some other permutation of the above which all give the same answer:

$
2^a + 2^b + 2^c = 2 + 4 + 8 = 14$