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Math Help - Integers (549)

  1. #1
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    Integers (549)

    If a, b, and c are different positive integers and (2^a )( 2^b) ( 2^c) =64, then 2^a + 2^b +2^c =

    (2^a)(2^b)(2^c)--> multiply
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  2. #2
    Senior Member Peritus's Avatar
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    if
    <br />
(2^a )( 2^b) ( 2^c) =64

    then:

    a + b + c = 6

    we're told that a,b,c are positive different integers so the only possible option is:

    a = 1, b = 2, c = 3

    or some other permutation of the above which all give the same answer:

    <br />
2^a  + 2^b  + 2^c  = 2 + 4 + 8 = 14
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