If a, b, and c are different positive integers and $\displaystyle (2^a )( 2^b) ( 2^c) =64, then 2^a + 2^b +2^c = $
(2^a)(2^b)(2^c)--> multiply
if
$\displaystyle
(2^a )( 2^b) ( 2^c) =64$
then:
$\displaystyle a + b + c = 6$
we're told that a,b,c are positive different integers so the only possible option is:
$\displaystyle a = 1, b = 2, c = 3$
or some other permutation of the above which all give the same answer:
$\displaystyle
2^a + 2^b + 2^c = 2 + 4 + 8 = 14$