# Math Help - The sum of another problematic sequence.

1. ## The sum of another problematic sequence.

That's the question and my working so far. I can't really see what the next step is or if this method will work out at the end.

Go back to the original series and substitute $\frac{1}{n(n+1)} = \frac{1}{n} - \frac{1}{n+1}$ ....