Function

**fabxx** · September 19th 2008, 09:15 AM

Let the function h be defined by h(x)=14+ $\frac{x^2}{4}$ . If h(2m)=9m, what is one possible value of m?

**Soroban** · September 19th 2008, 10:48 AM

Hello, fabxx!

I assume that is an equal-sign in there . . .

Let: . $h(x)\:=\:14+ \frac{x^2}{4}$ .
If $h(2m) \:{\color{red}=}\:9m$ , what is one possible value of $m$ ?

Since $h(2m) \:=\:14 + \frac{(2m)^2}{4} \:=\:14 + m^2$

. . we have: . $14 + m^2 \:=\:9m \quad\Rightarrow\quad m^2 - 9m + 14 \:=\:0$

Factor:. . $(m - 2)(m - 7) \:=\:0 \quad\Rightarrow\quad\boxed{ m \;=\;2,\;7}$

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