Hello, i am new to this site, an i was not sure where to post (as i am not in the US schooling system), i am doing AS level maths in the UK if this helps?
i need to rearrange equations to y=mx+c
5x+y=4
x-2y+6=0
x+2y=3
y-6=2(x+4) <-- No idea whatsoever.
I hope you can help me :S
I got to a later question, which was State whether the following were parallel, perpendicular, or neither, I managed to do the parallel ones, so i need now to know whether these were perpendicular or not
Is
perpencicular to
and
General equation is , where is the slope of the line and is the point of line intersecting the y-axis.
So, the slopes are ,
,
(now you know how to rearrange this) .
When equals the lines are parrarel (or the same), and when (where the is undefined, that is, denominator is 0; more at here) the lines are perpendicular. Now, you only need to compare those ks.
For , you will notice it has a slope of 3.
Now, a line is perpendicular to the above line if its slope is the inverse reciprocal - ie. slope of
does indeed have a slope of and so, it is perpendicular to the line.
Also:
And its slope is also and hence, it's perpendicular to the line.
Thanks a lot guys
That helped me, for the next 5 questions!
However i got stuck again.
Line q has the equation
(a) Give the equation of the line through parallel to q
(b) Give he equation of the line through perpendicular to q
I think (a) may well be
However, i am not confident of that one bit...