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Math Help - parabola

  1. #1
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    Sep 2008
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    parabola

    Hi, there's a graph to this question, but i don't know how to draw it here so i'll try my best to describe it. First of all the question: The graph below is a parabola that is symmetric about the x-axis. What is the equation of this parabola? The graph is a "sideways" parabola with an opening to the right. One a paired of sets is given, it is the vertex of the parabola which is (-2, O). The correct answer is x=y^2-2. I don't know how they got this answer. thanks again!
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  2. #2
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    Aug 2008
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    Hi fabxx

    If you're familiar with the basic parabola equation we typically use y = x^2
    this shouldn't be that hard,

    The parabola on its side is the same shape but uses the basic equation
    x = y^2, when using this equation there are several ways to manipulate the shape of the graph, from what you described we take the basic 'side' parabola x = y^2 (which we know is positive coz it opens in the positive x direction)

    To obtain a vertex of (-2,0) the parabola has simply been translated 2 points to the left, to change the equation we subtract 2 ie x = y^2 - 2
    -2 = 0^2 - 2 stands true and you can test that for other points on the curve

    Hope that helps
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