# Thread: Statics of a Particle

1. ## Statics of a Particle

Could someone help me with this problem
A weight of 20 kg is suspended from two strings of
length 10 cm and 12 cm, the ends of the strings being
attached to two points in a horizontal line, 15 cm apart.
Find the tension in each string.

The answer in the textbook is T1=14.99kg wt and T2=12.10kg wt, but i'm not sure how to get it. i tried finding the angles and then moving the vectors around but it wasn't right.

2. I won't do it, but the book is wrong. A tension is a force and its unit is commonly in newtons ( $N$), not $kg$.
Put the equations :
The system is in equilibrium, so the sum of the vertical components of the tensions are equal in magnitude to the weight. Take note that the weight is a force and its unit is not in $kg$ but in $N$. The object has a mass of $20 kg$ which means $20kg\cdot \frac{9.8m}{s^2}=196N$.

3. what are the vertical components of the tensions and how would you figure them out? would finding them help to solve the problem? would it be possible to use kilogram weight as the force instead of newtons, or does it have to be N? sorry but i still dont know how to work it out

what are the vertical components of the tensions and how would you figure them out? would finding them help to solve the problem? would it be possible to use kilogram weight as the force instead of newtons, or does it have to be N? sorry but i still dont know how to work it out
I don't have the time to do it for now. I think you can work out the vertical components of the tensions by calculating the angles that are into the triangle formed by the strings and the ceiling.
Yes, finding them would help to solve the problem. You have to put down equations.
For example you know that the horizontal components of the tensions $T_1$ and $T_2$ are equal in magnitude and opposite in sense because the system is at equilibrium. If they are not equal in magnitude, then the system would be moving with an acceleration which is not the case.
So put down the equations for the "x-axis" and the "y-axis" that you may want to define in the same direction than the figure is.
On the x-axis you have that the horizontal component of $T_1$ times i unit vector $+$ horizontal component of $T_2$ times i unit vector is equal to $0$.
I call $T_{1ver}$ the vertical component of $T_1$ and $T_{2ver}$ the vertical component of $T_2$. For the y-axis you have that $T_{1ver}+T_{2ver}=\text{weight of the mass}$.
And I'm sorry, your book is probably right about the weight. The weight is a force and the SI unit for it is the newton, $N$ which is worth $\frac{1kgm}{s^2}$, but I misread what your book says, it says $kg\cdot wt$. I never saw that before but it is probably a possible unit for a force. So excuse me here.
Also pardon my poor quality answer to your problem. Maybe try to post it on http://www.physicshelpforum.com/physics-help/....
That's a nice problem though, and I'll try to solve it maybe next week so don't wait for me. Good luck.