Solve the following quadratic equation: It *should* be solved using new variable, but I can't figure it out for x^3.
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Hello, Originally Posted by courteous Solve the following quadratic equation: It *should* be solved using new variable, but I can't figure it out for x^3. So if you substitute , you'll have ... ?
Yes, of course. Be aware though, I'll get to you with some other fuzzy quadratic.
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