Results 1 to 3 of 3

Math Help - [SOLVED] Quadratic equation

  1. #1
    Member courteous's Avatar
    Joined
    Aug 2008
    From
    big slice of heaven
    Posts
    206

    Question [SOLVED] Quadratic equation

    Solve the following quadratic equation:
    (x^2-4x)^2 -26(x^2-4x)+105=0
    It *should* be solved using new variable, but I can't figure it out for x^3.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Hello,
    Quote Originally Posted by courteous View Post
    Solve the following quadratic equation:
    (x^2-4x)^2 -26(x^2-4x)+105=0
    It *should* be solved using new variable, but I can't figure it out for x^3.
    ({\color{red}x^2-4x})^2 -26({\color{red}x^2-4x})+105=0

    So if you substitute y={\color{red}x^2-4x}, you'll have ... ?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member courteous's Avatar
    Joined
    Aug 2008
    From
    big slice of heaven
    Posts
    206

    Red face Sorry...

    Yes, of course.

    Be aware though, I'll get to you with some other fuzzy quadratic.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Quadratic equation
    Posted in the Algebra Forum
    Replies: 3
    Last Post: February 23rd 2010, 11:02 AM
  2. Replies: 6
    Last Post: February 13th 2010, 02:41 PM
  3. [SOLVED] Help on Quadratic Equation
    Posted in the Algebra Forum
    Replies: 3
    Last Post: September 3rd 2009, 12:56 PM
  4. [SOLVED] Quadratic Equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: November 27th 2008, 12:20 PM
  5. [SOLVED] Quadratic Equation
    Posted in the Algebra Forum
    Replies: 12
    Last Post: May 2nd 2008, 12:06 PM

Search Tags


/mathhelpforum @mathhelpforum