1. ## Math Question combination

A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
(a) How many bicycles can be manufactured using these parts?

(b) How many parts of each kind are left over?

2. Originally Posted by qbkr21
A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
(a) How many bicycles can be manufactured using these parts?

(b) How many parts of each kind are left over?
Each bicycle needs two wheels, one frame and one handlebar.

(a) We want to see which of this is the lowest value. For:
• Wheels: $4813 \div 2 = 2406.5$. So, $2406$ bicycles can be made.
• Frames: $2304$ bicycles can be made.
• Handlebars: $2254$ can be made.
The lowest value is $2254$ hence $2254$ bicycles can be manufactured.

(b) We subtract $2254$ for each parts.
• Wheels: $2406.5 - 2254 = 152.5$. So, $153$ wheels remain (As $0.5$ wheel of $2$ is $1$ wheel).
• Frames: $2304 - 2254 = 50$. So, $50$ frames remain.
• Handlebars: $2254 - 2254 = 0$. No handlebars remain.