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    Math Question combination

    A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
    (a) How many bicycles can be manufactured using these parts?

    (b) How many parts of each kind are left over?
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    Quote Originally Posted by qbkr21 View Post
    A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
    (a) How many bicycles can be manufactured using these parts?

    (b) How many parts of each kind are left over?
    Each bicycle needs two wheels, one frame and one handlebar.

    (a) We want to see which of this is the lowest value. For:
    • Wheels: 4813 \div 2 = 2406.5. So, 2406 bicycles can be made.
    • Frames: 2304 bicycles can be made.
    • Handlebars: 2254 can be made.
    The lowest value is 2254 hence 2254 bicycles can be manufactured.

    (b) We subtract 2254 for each parts.
    • Wheels: 2406.5 - 2254 = 152.5. So, 153 wheels remain (As 0.5 wheel of 2 is 1 wheel).
    • Frames: 2304 - 2254  = 50. So, 50 frames remain.
    • Handlebars: 2254 - 2254 = 0. No handlebars remain.
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