1. ## Math Question combination

A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
(a) How many bicycles can be manufactured using these parts?

(b) How many parts of each kind are left over?

2. Originally Posted by qbkr21
A manufacturer of bicycles has 4813 wheels, 2304 frames, and 2254 handlebars.
(a) How many bicycles can be manufactured using these parts?

(b) How many parts of each kind are left over?
Each bicycle needs two wheels, one frame and one handlebar.

(a) We want to see which of this is the lowest value. For:
• Wheels: $\displaystyle 4813 \div 2 = 2406.5$. So, $\displaystyle 2406$ bicycles can be made.
• Frames: $\displaystyle 2304$ bicycles can be made.
• Handlebars: $\displaystyle 2254$ can be made.
The lowest value is $\displaystyle 2254$ hence $\displaystyle 2254$ bicycles can be manufactured.

(b) We subtract $\displaystyle 2254$ for each parts.
• Wheels: $\displaystyle 2406.5 - 2254 = 152.5$. So, $\displaystyle 153$ wheels remain (As $\displaystyle 0.5$ wheel of $\displaystyle 2$ is $\displaystyle 1$ wheel).
• Frames: $\displaystyle 2304 - 2254 = 50$. So, $\displaystyle 50$ frames remain.
• Handlebars: $\displaystyle 2254 - 2254 = 0$. No handlebars remain.