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Thread: Conversions Again

  1. #1
    Member >_<SHY_GUY>_<'s Avatar
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    Unhappy Conversions Again

    I Am So Lost...I Try Getting To Convert One Unit To The One I Need. The Math Is Good....Yet I Come With The Wrong Answer

    A Block Of Of Ice Measures 14.5 cm. by 6.4 in. by 1.05 x 10^-4 km.
    How Much Would The Cube Weight If The Density Of Ice Is 0.98 g. Per Cubic Centimeters.
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  2. #2
    Super Member 11rdc11's Avatar
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    1st convert everything to cm and then multiply the 3 measurements to get $\displaystyle cm^3$

    $\displaystyle \bigg(\frac{6.4in}{1}\bigg)\bigg(\frac{2.54cm}{1in }\bigg) =$

    $\displaystyle \bigg(\frac{1.05 X 10^{-4}km}{1}\bigg)\bigg(\frac{100000cm}{1km}\bigg) =$
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  3. #3
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    Quote Originally Posted by >_<SHY_GUY>_< View Post
    I Am So Lost...I Try Getting To Convert One Unit To The One I Need. The Math Is Good....Yet I Come With The Wrong Answer

    A Block Of Of Ice Measures 14.5 cm. by 6.4 in. by 1.05 x 10^-4 km.
    How Much Would The Cube Weight If The Density Of Ice Is 0.98 g. Per Cubic Centimeters.
    1 inch = 2.54 cm

    $\displaystyle 1 km = 10^5 cm$ convert all units to cm. {because density is given in $\displaystyle g/cm^3$}

    volume of cube $\displaystyle = 14.5 \times (6.4 \times 2.54) \times [(1.05\times 10^{-4})\times (10^5)]$

    $\displaystyle
    = 14.5 \times 16.256 \times 10.5$

    $\displaystyle =2474.976 cm^3$

    mass = volume \times density

    $\displaystyle
    = 2474.976 \times 0.98$

    = 2425.48 grams

    = 2.425 kg
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