Math Help - chemistry problem

1. chemistry problem

(22.4g - 8.3g)/(1.143mL - 0.002mL)

=

14.1g/ 1.140
-----------^ that arrow is pointing to that zero cause that is where my first problem occured. do i add that 0? cause in the orignal denominator the 1.143 has 3 significant values after the decimal and .002 has 3 numbers after the decimal but only 1 significant. So do i leave it as 1.140 or 1.14 or 1.1??

14.1g/1.140mL = 12.4g/ml cause 14.1 = 3sig figs... i think.

2. You only take into account of significant figures after you do the calculation. Doing it midway will often throw your result way off from the theoretical.

So: $\frac{22.4 \text{g} - 8.3 \text{g}}{ 1.143 \text{mL} - 0.00{\color{red}2} \text{mL}}= \frac{14.1 \text{g}}{1.141 \text{mL}} = 12.3575... \text{g} / \text{mL} \ \rightarrow \ {\color{red}1}0 \text{g} / \text{mL}$

One significant figure is needed since 0.002 is the least accurate measurement.