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Simplify using log laws: 2loga(6xy)^3 - loga(3xy) + xloga(1)

Quote: Originally Posted by Monorail Simplify using log laws: 2loga(6xy)^3 - loga(3xy) + xloga(1) $\displaystyle \equiv \log_a (6xy)^6 - \log_a (3xy) + x (0)$ etc.