I am stuck!
qbkr21
I thought the radial value was 8.35 mm = .835 cm
So $\displaystyle V=\pi r^2h\implies 7.14\times10^3~cm^3=\pi(.835~cm)^2h$
Solving for h, we see that $\displaystyle h=\frac{7.14\times10^3~cm^3}{\pi(.835~cm)^2}\appro x\color{red}\boxed{3.26\times10^3 ~cm}$
Does this make sense?
--Chris
EDIT: I see now that .835 cm was the diameter...my mistake...
The equation should be $\displaystyle V=\pi r^2h\implies 7.14\times10^3~cm^3=\pi(.4175~cm)^2h$
Solving for h, we see that $\displaystyle h=\frac{7.14\times10^3~cm^3}{\pi(.4175~cm)^2}\appr ox\color{red}\boxed{1.3\times10^4 ~cm}$
Thanks for the response, but how do you figure the radial value = 8.35 when the problem states that it is the diameter. I divided by 2 (a half) to get the radius. From there I would still be stuck in millimeters. I was thinking about then going over to volume and converting it into millimeters cubed, then dividing it by pi and (4.175 mm)^2. I'd then be left will millimeters of which I could covert back into feet. Does this work or am I making it way to complicated?