simplify (y–2/y8)(1/y–3) please. I cannot figure it out.
For fractions, when multiplying, you mupltiply the numerator with the numerator and the denominator with the denominator.
Is your question:
$\displaystyle \left(\frac{y^{-2}}{y^8}\right)\left(\frac{1}{y^{-3}}\right)$
Or
$\displaystyle \left(\frac{y-2}{8y}\right)\left(\frac{1}{y-3}\right)$
Or
Something else?