# simplify (y–2/y8)(1/y–3) please. I cannot figure it out.

• Aug 24th 2008, 10:00 AM
plumbob
simplify (y–2/y8)(1/y–3) please. I cannot figure it out.
simplify (y–2/y8)(1/y–3) please. I cannot figure it out.
• Aug 24th 2008, 10:16 AM
skeeter
how come I get the feeling that the -2, 8, and -3 are all exponents ?

is this what you mean ?

$\displaystyle \frac{y^{-2}}{y^8} \cdot \frac{1}{y^{-3}}$
• Aug 24th 2008, 10:19 AM
Simplicity
Quote:

Originally Posted by plumbob
simplify (y–2/y8)(1/y–3) please. I cannot figure it out.

For fractions, when multiplying, you mupltiply the numerator with the numerator and the denominator with the denominator.

$\displaystyle \left(\frac{y^{-2}}{y^8}\right)\left(\frac{1}{y^{-3}}\right)$

Or

$\displaystyle \left(\frac{y-2}{8y}\right)\left(\frac{1}{y-3}\right)$

Or

Something else? :confused:
• Aug 24th 2008, 10:38 AM
plumbob
Those may be exponents,....
The Prof. wrote the problem out exactly like that. They may be exponents, I am not sure, thanks for the replys.

Chris