simplify (y–2/y8)(1/y–3) please. I cannot figure it out.

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- Aug 24th 2008, 10:00 AMplumbobsimplify (y–2/y8)(1/y–3) please. I cannot figure it out.
simplify (y–2/y8)(1/y–3) please. I cannot figure it out.

- Aug 24th 2008, 10:16 AMskeeter
how come I get the feeling that the -2, 8, and -3 are all exponents ?

is this what you mean ?

$\displaystyle \frac{y^{-2}}{y^8} \cdot \frac{1}{y^{-3}}$ - Aug 24th 2008, 10:19 AMSimplicity
For fractions, when multiplying, you mupltiply the numerator with the numerator and the denominator with the denominator.

Is your question:

$\displaystyle \left(\frac{y^{-2}}{y^8}\right)\left(\frac{1}{y^{-3}}\right)$

Or

$\displaystyle \left(\frac{y-2}{8y}\right)\left(\frac{1}{y-3}\right)$

Or

Something else? :confused: - Aug 24th 2008, 10:38 AMplumbobThose may be exponents,....
The Prof. wrote the problem out exactly like that. They may be exponents, I am not sure, thanks for the replys.

Chris