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Math Help - Need help simplfying some expressions

  1. #1
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    Need help simplfying some expressions

    81 x ^10 y^6 divided by (3x^2 y) ^4

    6x+18 over x plus 3


    12c^2 divided by 3c +6
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  2. #2
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    Quote Originally Posted by Laura901 View Post
    81 x ^10 y^6 divided by (3x^2 y) ^4

    6x+18 over x plus 3


    12c^2 divided by 3c +6
    1. start by expanding the bottom...

    3^4 * (x^2)^4 * y^4 =
    81x^8y^4

    now cancel like terms
    the 81 is removed completely
    x^10/x^8 = x^2
    y^6/y^4 = y^2

    final answer: x^2 * y^2
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  3. #3
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    Quote Originally Posted by Laura901 View Post
    81 x ^10 y^6 divided by (3x^2 y) ^4

    6x+18 over x plus 3


    12c^2 divided by 3c +6
    I will provide you with rules through which you will be able to conduct the questions.
    __________________

    \frac{81x^{10}y^{6}}{(3x^2y)^4}

    Use these rules:
    (x^ay^b)^c = x^{ac}y^{bc}
    \frac{a^xb^y}{a^sb^t} = a^{x-s}b^{y-t}

    Use the rules stated above then simplify the expression.
    __________________

    \frac{6x+18}{x + 3}

    Use this rule:
    Factorising ax+bx = x(a+b)

    Factorise the numerator and then simplify the expression.
    __________________

    \frac{12c^2}{3c +6}

    Use this rule:
    Factorising ax+bx = x(a+b)

    Factorise the denominator and then simplify the expression.
    Last edited by Simplicity; August 11th 2008 at 08:14 AM. Reason: Latex Correction
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  4. #4
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    Quote Originally Posted by Laura901 View Post
    12c^2 divided by 3c +6
    \frac{12c^2}{3c+6}=\frac{ 3\cdot 4c^2}{3(c+2)} =\frac{\not 3\cdot 4c^2}{\not 3(c+2)} = \frac{4c^2}{c+2}
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