Hey,
I have this question thats been bugging me for a few days now.
$\displaystyle 3y-15=2x-8$
Whats the answer if we put it in the eqN of a line?
$\displaystyle 2x-3y+7=0$ OR $\displaystyle 2x-3y-7=0$?
Thanks for the help.
-NZF
Hey,
I have this question thats been bugging me for a few days now.
$\displaystyle 3y-15=2x-8$
Whats the answer if we put it in the eqN of a line?
$\displaystyle 2x-3y+7=0$ OR $\displaystyle 2x-3y-7=0$?
Thanks for the help.
-NZF
alright, standard form is in the form of $\displaystyle ax+by=c$ therefore we start with your equation...Originally Posted by NineZeroFive
$\displaystyle 3y-15=2x-8$
add 15 to both sides $\displaystyle 3y=2x-8+15$
subtract 2x from both sides: $\displaystyle 3y-2x=7$
voila!
~ $\displaystyle Q\!u\!i\!c\!k$
Algebraically it would have to be $\displaystyle 2x-3y+7=0$. Other standard forms:Originally Posted by NineZeroFive
$\displaystyle y = \frac{2}{3}x + \frac{7}{3}$ (Slope - Intercept form)
and
$\displaystyle (y - 3) = \frac{2}{3}(x - 1)$ (An example of point-slope form)
and
$\displaystyle \frac{x}{3} - \frac{y}{2} = - \frac{7}{6}$ (I forget what this one is called.)
-Dan
One standard way of writing a multinomial (the "most" standard I've seen, if there is such a thing) is to write the terms of highest degree first down to the lowest degree such that the expression equals zero. For example:Originally Posted by Quick
$\displaystyle 3x^2y^3 - xy^2 + 12x - 3y + 5 = 0$
In the case for a linear equation the form simply becomes:
$\displaystyle ax + by + c = 0$
I'll admit I don't usually see this form for a line, but considering the expression as a multinomial it would be standard.
-Dan