1. ## Set theory

The following data is obtained from a high school from a population of 1600 students.

801 passed Math
900 passed Physics
752 passed Chemistry
435 passed Math and Physics
398 passed Math and Chemistry
412 passsed Physics and Chemistry
310 passed Math, Chemistry and Physics

Calculate how many students passed only one subject.

2. Originally Posted by bret80
The following data is obtained from a high school from a population of 1600 students.

801 passed Math
900 passed Physics
752 passed Chemistry
435 passed Math and Physics
398 passed Math and Chemistry
412 passsed Physics and Chemistry
310 passed Math, Chemistry and Physics

Calculate how many students passed only one subject.
As 310 passed all three, 412-310=102 passed only P&C, 398-310=88 passed only
M&C, and 435-310=125 passed only M&P.

Therefore

801-310-88-125=278 passed only M,
900-310-102-125=363 passed only P,
752-310-102-88=252 passed only C.

So the number that passed only one subject is 278+363+252=893

RonL

3. Hello, bret80!

The following data is obtained from a high school from a population of 1600 students.

801 passed Math
900 passed Physics
752 passed Chemistry
435 passed Math and Physics
398 passed Math and Chemistry
412 passsed Physics and Chemistry
310 passed Math, Chemistry and Physics

Calculate how many students passed only one subject.

You need to construct a Venn diagram.
Code:
          * - - - - - *
| M  278    |
|   * - - - + - *
|   |   125 |   |
* - + - + - *   +   |
|   | 88|310|   |   |
|   * - + - + - *   |
|       |   | 363 P |
|       * - + - - - *
| C 252     |
* - - - - - *

Students passing one course: .$\displaystyle 278 + 363 + 252 \,= \,893$