without graphing or using any algebraic methods determine whether or not there is a solution to the following
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That is an utterly silly request. What's left, Astrology?
Easiest determination, in my view 3(-2) - 6(1) = -6 - 6 = -12 this is not zero (0). There is a unique solution. However, addition and subtraction seem awfully "algebraic" to me.
Originally Posted by euclid2 without graphing or using any algebraic methods determine whether or not there is a solution to the following
6x-2y=3 If you have asystem of linear equations like:
then there exist a unique solution if the determinant
With your example and therefore there must be an unique solution.
3x + y would be half of 6x-2y except for the operator. You are left with 6x=4 and 6x=3. Again, this does use algebraic concepts, but I just did it without the equations.
i was thinking if you went
Since the X are the same when multiplied by two i thought there would be no solution
but if you end up with
then one of the 6x would have to be -6x for them to cancel
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