sin x=5/13 tan x=-5/12 ;x=?

Results 1 to 5 of 5

- Aug 3rd 2008, 07:46 AM #1

- Joined
- Aug 2008
- Posts
- 1

- Aug 3rd 2008, 07:57 AM #2

- Aug 3rd 2008, 08:10 AM #3

- Aug 3rd 2008, 08:34 AM #4

- Aug 3rd 2008, 10:58 AM #5

- Joined
- Jan 2008
- From
- Big Stone Gap, Virginia
- Posts
- 2,550
- Thanks
- 15
- Awards
- 1

You're looking for an angle whose terminal side is in the second quadrant, since that's the quadrant where

is positive and*Sin*is negative.*Tan*

$\displaystyle \theta=\arcsin\left(\frac{5}{13}\right)\approx22.6 ^\circ$

The reference angle in the 2nd quadrant is $\displaystyle 22.6^\circ$

For any angle $\displaystyle \theta, \ \ 0 < \theta < 180^\circ$, its reference angle is defined as $\displaystyle 180^\circ - \theta$

$\displaystyle \theta = 180^\circ - 22.6^\circ \approx 157.4^\circ$

Click on a term to search for related topics.